化验专业冬训试题

X=                                    1
          G
   56.1×0.0219×(0.07-0.03)
 =                                         2
           10
 =0.0049(mgKOH/g)                          1
答：油的酸值为0.0049(mgKOH/g)              1

3、
解：
X2   =  P2  .  T1
    X1      P1     T2                            
                                               
X2 = P2  .  T1  . X1
          P1     T2
   
      =  2338.54Χ(273+5)Χ71.15                                    
         872.469Χ(273+20)                       
     =180.94ppm
 
答：换算为20℃时的微水值为180.94ppm  。

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